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Multiple choice📘 F.IF.C.8🧠 DOK 3
Question:
Consider the quadratic function f(x) = x^2 - 6x + 9. Which of the following forms of the function reveals that the vertex of the parabola is at the point (3, 0)?
Answer Choices:
- A) f(x) = (x - 3)^2
- B) f(x) = x^2 - 6x + 9
- C) f(x) = (x - 3)(x - 3)
- D) f(x) = (x - 3)^2 + 0
✅ Answer:
f(x) = (x - 3)^2
💡 Explanation:
The vertex form of a quadratic function is f(x) = a(x - h)^2 + k, where (h, k) is the vertex of the parabola.
By rewriting the function f(x) = x^2 - 6x + 9 as f(x) = (x - 3)^2, it is clear that the vertex is at (3, 0).
The original function is already in a form that can be easily converted to vertex form by completing the square.
Standard: F.IF.C.8 | DOK: 3